Look at the table of values for the functions and
f
(
x
)
=
absolute value bar
x
–
6
absolute value bar
g
(
x
)
=
2
x
+
3
.x | f ( x ) | g ( x ) |
– | 7 | 7 2 |
| 0 | 6 | 4 |
| 1 | 5 | 5 |
| 2 | 4 | 7 |
| 3 | 3 | 11 |
Based on the values in the table, where does the equation have a solution?
f
(
x
)
=
g
(
x
)
x
=
1
between and
x
=
1
x
=
2
x
=
2
between and
x
=
2
x
=
3
ref_doc_title.
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